Base | Representation |
---|---|
bin | 111100010100110100000110… |
… | …101000110010000110110111 |
3 | 1021210101200112221012020010201 |
4 | 330110310012220302012313 |
5 | 234233342240242130403 |
6 | 2340135100104101331 |
7 | 106612145411360662 |
oct | 7424640650620667 |
9 | 1253350487166121 |
10 | 265313126130103 |
11 | 7759a735002017 |
12 | 2590b565164847 |
13 | b506bc72940cc |
14 | 497331c2446d9 |
15 | 20a160b08b21d |
hex | f14d06a321b7 |
265313126130103 has 2 divisors, whose sum is σ = 265313126130104. Its totient is φ = 265313126130102.
The previous prime is 265313126130089. The next prime is 265313126130139. The reversal of 265313126130103 is 301031621313562.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 265313126130103 - 221 = 265313124032951 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (265313126136103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132656563065051 + 132656563065052.
It is an arithmetic number, because the mean of its divisors is an integer number (132656563065052).
Almost surely, 2265313126130103 is an apocalyptic number.
265313126130103 is a deficient number, since it is larger than the sum of its proper divisors (1).
265313126130103 is an equidigital number, since it uses as much as digits as its factorization.
265313126130103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 58320, while the sum is 37.
Adding to 265313126130103 its reverse (301031621313562), we get a palindrome (566344747443665).
The spelling of 265313126130103 in words is "two hundred sixty-five trillion, three hundred thirteen billion, one hundred twenty-six million, one hundred thirty thousand, one hundred three".
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