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2657181317053 is a prime number
BaseRepresentation
bin100110101010101100010…
…110010011011110111101
3100102000122112102210002211
4212222230112103132331
5322013401404121203
65352405305220421
7362655300350164
oct46525426233675
910360575383084
102657181317053
119349a46431aa
1236ab90791711
131637569aca13
14928730dc3db
15491bcdc2c6d
hex26aac5937bd

2657181317053 has 2 divisors, whose sum is σ = 2657181317054. Its totient is φ = 2657181317052.

The previous prime is 2657181316919. The next prime is 2657181317057. The reversal of 2657181317053 is 3507131817562.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2637837236164 + 19344080889 = 1624142^2 + 139083^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2657181317053 is a prime.

It is a super-2 number, since 2×26571813170532 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2657181316988 and 2657181317006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2657181317057) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1328590658526 + 1328590658527.

It is an arithmetic number, because the mean of its divisors is an integer number (1328590658527).

Almost surely, 22657181317053 is an apocalyptic number.

It is an amenable number.

2657181317053 is a deficient number, since it is larger than the sum of its proper divisors (1).

2657181317053 is an equidigital number, since it uses as much as digits as its factorization.

2657181317053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1058400, while the sum is 49.

The spelling of 2657181317053 in words is "two trillion, six hundred fifty-seven billion, one hundred eighty-one million, three hundred seventeen thousand, fifty-three".