Base | Representation |
---|---|
bin | 100110111101111111011… |
… | …101110011100100001111 |
3 | 100111000010200012201110112 |
4 | 212331333131303210033 |
5 | 322333321201121411 |
6 | 5410113422030235 |
7 | 364320636110336 |
oct | 46757735634417 |
9 | 10430120181415 |
10 | 2677903145231 |
11 | 942768570436 |
12 | 372bb441837b |
13 | 1656a9a9a302 |
14 | 9387b200d1d |
15 | 499d21c3b8b |
hex | 26f7f77390f |
2677903145231 has 2 divisors, whose sum is σ = 2677903145232. Its totient is φ = 2677903145230.
The previous prime is 2677903145209. The next prime is 2677903145261. The reversal of 2677903145231 is 1325413097762.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2677903145231 - 234 = 2660723276047 is a prime.
It is a super-4 number, since 4×26779031452314 (a number of 51 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 2677903145231.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2677903145261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1338951572615 + 1338951572616.
It is an arithmetic number, because the mean of its divisors is an integer number (1338951572616).
Almost surely, 22677903145231 is an apocalyptic number.
2677903145231 is a deficient number, since it is larger than the sum of its proper divisors (1).
2677903145231 is an equidigital number, since it uses as much as digits as its factorization.
2677903145231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1905120, while the sum is 50.
The spelling of 2677903145231 in words is "two trillion, six hundred seventy-seven billion, nine hundred three million, one hundred forty-five thousand, two hundred thirty-one".
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