268140227 has 2 divisors, whose sum is σ = 268140228. Its totient is φ = 268140226.

The previous prime is 268140203. The next prime is 268140239. The reversal of 268140227 is 722041862.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 268140227 - 2⁶ = 268140163 is a prime.

It is a super-3 number, since 3×268140227³ (a number of 26 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 268140193 and 268140202.

It is not a weakly prime, because it can be changed into another prime (268140127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 134070113 + 134070114.

It is an arithmetic number, because the mean of its divisors is an integer number (134070114).

Almost surely, 2^268140227 is an apocalyptic number.

268140227 is a deficient number, since it is larger than the sum of its proper divisors (1).

268140227 is an equidigital number, since it uses as much as digits as its factorization.

268140227 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10752, while the sum is 32.

The square root of 268140227 is about 16374.9878473237. The cubic root of 268140227 is about 644.8430016698.

The spelling of 268140227 in words is "two hundred sixty-eight million, one hundred forty thousand, two hundred twenty-seven".