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26989401349 is a prime number
BaseRepresentation
bin11001001000101100…
…011001010100000101
32120122221022122102101
4121020230121110011
5420233241320344
620222044312101
71643552061211
oct311054312405
976587278371
1026989401349
111049a8a4779
125292842631
13271173c691
141440683941
15a7e68e9d4
hex648b19505

26989401349 has 2 divisors, whose sum is σ = 26989401350. Its totient is φ = 26989401348.

The previous prime is 26989401337. The next prime is 26989401353. The reversal of 26989401349 is 94310498962.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20855692225 + 6133709124 = 144415^2 + 78318^2 .

It is a cyclic number.

It is not a de Polignac number, because 26989401349 - 217 = 26989270277 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 26989401349.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (26989401149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13494700674 + 13494700675.

It is an arithmetic number, because the mean of its divisors is an integer number (13494700675).

Almost surely, 226989401349 is an apocalyptic number.

It is an amenable number.

26989401349 is a deficient number, since it is larger than the sum of its proper divisors (1).

26989401349 is an equidigital number, since it uses as much as digits as its factorization.

26989401349 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3359232, while the sum is 55.

The spelling of 26989401349 in words is "twenty-six billion, nine hundred eighty-nine million, four hundred one thousand, three hundred forty-nine".