Base | Representation |
---|---|
bin | 1100010001100100001110… |
… | …10000111001000000000111 |
3 | 10112120101200000011121220021 |
4 | 12020302013100321000013 |
5 | 12014213244010340012 |
6 | 133223514252520011 |
7 | 5454045024045034 |
oct | 610620720710007 |
9 | 115511600147807 |
10 | 26991843840007 |
11 | 86671a4198692 |
12 | 303b249a80007 |
13 | 120a420c21597 |
14 | 6945ab17a38b |
15 | 31c1be4e0007 |
hex | 188c87439007 |
26991843840007 has 2 divisors, whose sum is σ = 26991843840008. Its totient is φ = 26991843840006.
The previous prime is 26991843839971. The next prime is 26991843840011. The reversal of 26991843840007 is 70004834819962.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 26991843840007 - 243 = 18195750817799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (26991843840037) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13495921920003 + 13495921920004.
It is an arithmetic number, because the mean of its divisors is an integer number (13495921920004).
Almost surely, 226991843840007 is an apocalyptic number.
26991843840007 is a deficient number, since it is larger than the sum of its proper divisors (1).
26991843840007 is an equidigital number, since it uses as much as digits as its factorization.
26991843840007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20901888, while the sum is 61.
The spelling of 26991843840007 in words is "twenty-six trillion, nine hundred ninety-one billion, eight hundred forty-three million, eight hundred forty thousand, seven".
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