Base | Representation |
---|---|
bin | 11001010001111000… |
… | …001000010101000011 |
3 | 2121001200020021020111 |
4 | 121101320020111003 |
5 | 421042212104301 |
6 | 20245230452151 |
7 | 1650432465124 |
oct | 312170102503 |
9 | 77050207214 |
10 | 27143472451 |
11 | 10569867667 |
12 | 5316364057 |
13 | 2737635604 |
14 | 1456d0c04b |
15 | a8ce75551 |
hex | 651e08543 |
27143472451 has 2 divisors, whose sum is σ = 27143472452. Its totient is φ = 27143472450.
The previous prime is 27143472353. The next prime is 27143472481. The reversal of 27143472451 is 15427434172.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 27143472451 - 215 = 27143439683 is a prime.
It is a super-3 number, since 3×271434724513 (a number of 32 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (27143472481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13571736225 + 13571736226.
It is an arithmetic number, because the mean of its divisors is an integer number (13571736226).
Almost surely, 227143472451 is an apocalyptic number.
27143472451 is a deficient number, since it is larger than the sum of its proper divisors (1).
27143472451 is an equidigital number, since it uses as much as digits as its factorization.
27143472451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 188160, while the sum is 40.
The spelling of 27143472451 in words is "twenty-seven billion, one hundred forty-three million, four hundred seventy-two thousand, four hundred fifty-one".
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