Base | Representation |
---|---|
bin | 11001100110100110… |
… | …110111111100000111 |
3 | 2121221220200020100021 |
4 | 121212212313330013 |
5 | 422300231123112 |
6 | 20343533200011 |
7 | 1662154641256 |
oct | 314646677407 |
9 | 77856606307 |
10 | 27491270407 |
11 | 10728118397 |
12 | 53b2930007 |
13 | 27916ca413 |
14 | 148b1a479d |
15 | aad776907 |
hex | 6669b7f07 |
27491270407 has 2 divisors, whose sum is σ = 27491270408. Its totient is φ = 27491270406.
The previous prime is 27491270393. The next prime is 27491270413. The reversal of 27491270407 is 70407219472.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 27491270407 - 215 = 27491237639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (27491279407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13745635203 + 13745635204.
It is an arithmetic number, because the mean of its divisors is an integer number (13745635204).
Almost surely, 227491270407 is an apocalyptic number.
27491270407 is a deficient number, since it is larger than the sum of its proper divisors (1).
27491270407 is an equidigital number, since it uses as much as digits as its factorization.
27491270407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 197568, while the sum is 43.
Adding to 27491270407 its reverse (70407219472), we get a palindrome (97898489879).
The spelling of 27491270407 in words is "twenty-seven billion, four hundred ninety-one million, two hundred seventy thousand, four hundred seven".
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