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2750444113 is a prime number
BaseRepresentation
bin1010001111110000…
…0111001001010001
321002200110001000111
42203330013021101
521113103202423
61132531321321
7125105250334
oct24374071121
97080401014
102750444113
11119161040a
12649150241
1334aa99031
141c140461b
151116eb60d
hexa3f07251

2750444113 has 2 divisors, whose sum is σ = 2750444114. Its totient is φ = 2750444112.

The previous prime is 2750444111. The next prime is 2750444119. The reversal of 2750444113 is 3114440572.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2029682704 + 720761409 = 45052^2 + 26847^2 .

It is a cyclic number.

It is not a de Polignac number, because 2750444113 - 21 = 2750444111 is a prime.

Together with 2750444111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (2750444111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1375222056 + 1375222057.

It is an arithmetic number, because the mean of its divisors is an integer number (1375222057).

Almost surely, 22750444113 is an apocalyptic number.

It is an amenable number.

2750444113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2750444113 is an equidigital number, since it uses as much as digits as its factorization.

2750444113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13440, while the sum is 31.

The square root of 2750444113 is about 52444.6766888690. The cubic root of 2750444113 is about 1401.0950807889.

Adding to 2750444113 its reverse (3114440572), we get a palindrome (5864884685).

It can be divided in two parts, 27504 and 44113, that added together give a palindrome (71617).

The spelling of 2750444113 in words is "two billion, seven hundred fifty million, four hundred forty-four thousand, one hundred thirteen".