Base | Representation |
---|---|
bin | 101000000110000001111… |
… | …010100100000100100111 |
3 | 100202101210100211110212111 |
4 | 220012001322210010213 |
5 | 330120224413242303 |
6 | 5505425051501451 |
7 | 403026516414232 |
oct | 50060172440447 |
9 | 10671710743774 |
10 | 2755253649703 |
11 | 972550946295 |
12 | 385ba0a57887 |
13 | 16ca8601c599 |
14 | 974d8132419 |
15 | 4ba0cc86b6d |
hex | 28181ea4127 |
2755253649703 has 2 divisors, whose sum is σ = 2755253649704. Its totient is φ = 2755253649702.
The previous prime is 2755253649691. The next prime is 2755253649727. The reversal of 2755253649703 is 3079463525572.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2755253649703 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2755253649763) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1377626824851 + 1377626824852.
It is an arithmetic number, because the mean of its divisors is an integer number (1377626824852).
Almost surely, 22755253649703 is an apocalyptic number.
2755253649703 is a deficient number, since it is larger than the sum of its proper divisors (1).
2755253649703 is an equidigital number, since it uses as much as digits as its factorization.
2755253649703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 47628000, while the sum is 58.
The spelling of 2755253649703 in words is "two trillion, seven hundred fifty-five billion, two hundred fifty-three million, six hundred forty-nine thousand, seven hundred three".
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