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27796014853 is a prime number
BaseRepresentation
bin11001111000110001…
…011000011100000101
32122202011002212010121
4121320301120130011
5423411234433403
620434101021541
72002545141115
oct317061303405
978664085117
1027796014853
1110874142402
1254789b48b1
13280c899889
1414b9851045
15aca3c13bd
hex678c58705

27796014853 has 2 divisors, whose sum is σ = 27796014854. Its totient is φ = 27796014852.

The previous prime is 27796014769. The next prime is 27796014881. The reversal of 27796014853 is 35841069772.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18426162049 + 9369852804 = 135743^2 + 96798^2 .

It is a cyclic number.

It is not a de Polignac number, because 27796014853 - 29 = 27796014341 is a prime.

It is a super-2 number, since 2×277960148532 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 27796014853.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (27796014053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13898007426 + 13898007427.

It is an arithmetic number, because the mean of its divisors is an integer number (13898007427).

It is a 1-persistent number, because it is pandigital, but 2⋅27796014853 = 55592029706 is not.

Almost surely, 227796014853 is an apocalyptic number.

It is an amenable number.

27796014853 is a deficient number, since it is larger than the sum of its proper divisors (1).

27796014853 is an equidigital number, since it uses as much as digits as its factorization.

27796014853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2540160, while the sum is 52.

The spelling of 27796014853 in words is "twenty-seven billion, seven hundred ninety-six million, fourteen thousand, eight hundred fifty-three".