Base | Representation |
---|---|
bin | 1100101111101101011001… |
… | …10101011111101100011111 |
3 | 10200020102000221022120111121 |
4 | 12113312230311133230133 |
5 | 12133200421143423012 |
6 | 135335403420431411 |
7 | 5621632045225426 |
oct | 627665465375437 |
9 | 120212027276447 |
10 | 28027561311007 |
11 | 8a26470757155 |
12 | 3187b196a8567 |
13 | 1283cabc5943b |
14 | 6cc7810d42bd |
15 | 3390db7aaa07 |
hex | 197dacd5fb1f |
28027561311007 has 2 divisors, whose sum is σ = 28027561311008. Its totient is φ = 28027561311006.
The previous prime is 28027561310971. The next prime is 28027561311019. The reversal of 28027561311007 is 70011316572082.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-28027561311007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (28027561311067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14013780655503 + 14013780655504.
It is an arithmetic number, because the mean of its divisors is an integer number (14013780655504).
Almost surely, 228027561311007 is an apocalyptic number.
28027561311007 is a deficient number, since it is larger than the sum of its proper divisors (1).
28027561311007 is an equidigital number, since it uses as much as digits as its factorization.
28027561311007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 141120, while the sum is 43.
Adding to 28027561311007 its reverse (70011316572082), we get a palindrome (98038877883089).
The spelling of 28027561311007 in words is "twenty-eight trillion, twenty-seven billion, five hundred sixty-one million, three hundred eleven thousand, seven".
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