Base | Representation |
---|---|
bin | 1100110110011100101010… |
… | …10000010111000101100001 |
3 | 10201001112122211210111110201 |
4 | 12123032111100113011201 |
5 | 12200444111021400213 |
6 | 140034014252225201 |
7 | 5644436456112235 |
oct | 633162520270541 |
9 | 121045584714421 |
10 | 28259093934433 |
11 | 90056838a400a |
12 | 320497546b201 |
13 | 129ca8a015a6b |
14 | 6d9a66db65c5 |
15 | 34013d1996dd |
hex | 19b395417161 |
28259093934433 has 2 divisors, whose sum is σ = 28259093934434. Its totient is φ = 28259093934432.
The previous prime is 28259093934427. The next prime is 28259093934457. The reversal of 28259093934433 is 33443939095282.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 25782143622544 + 2476950311889 = 5077612^2 + 1573833^2 .
It is a cyclic number.
It is not a de Polignac number, because 28259093934433 - 213 = 28259093926241 is a prime.
It is not a weakly prime, because it can be changed into another prime (28259093934233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14129546967216 + 14129546967217.
It is an arithmetic number, because the mean of its divisors is an integer number (14129546967217).
Almost surely, 228259093934433 is an apocalyptic number.
It is an amenable number.
28259093934433 is a deficient number, since it is larger than the sum of its proper divisors (1).
28259093934433 is an equidigital number, since it uses as much as digits as its factorization.
28259093934433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 151165440, while the sum is 64.
The spelling of 28259093934433 in words is "twenty-eight trillion, two hundred fifty-nine billion, ninety-three million, nine hundred thirty-four thousand, four hundred thirty-three".
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