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28341475117 is a prime number
BaseRepresentation
bin11010011001010010…
…001001011100101101
32201011011111002221121
4122121102021130231
5431020404200432
621004144100541
72022220364224
oct323122113455
981134432847
1028341475117
111102402980a
1255ab604751
1328988aa927
14152c07bcbb
15b0d219197
hex69948972d

28341475117 has 2 divisors, whose sum is σ = 28341475118. Its totient is φ = 28341475116.

The previous prime is 28341475091. The next prime is 28341475171. The reversal of 28341475117 is 71157414382.

Together with next prime (28341475171) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17899496521 + 10441978596 = 133789^2 + 102186^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-28341475117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (28341475417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14170737558 + 14170737559.

It is an arithmetic number, because the mean of its divisors is an integer number (14170737559).

Almost surely, 228341475117 is an apocalyptic number.

It is an amenable number.

28341475117 is a deficient number, since it is larger than the sum of its proper divisors (1).

28341475117 is an equidigital number, since it uses as much as digits as its factorization.

28341475117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 188160, while the sum is 43.

Adding to 28341475117 its reverse (71157414382), we get a palindrome (99498889499).

The spelling of 28341475117 in words is "twenty-eight billion, three hundred forty-one million, four hundred seventy-five thousand, one hundred seventeen".