Base | Representation |
---|---|
bin | 1101000110010000011110… |
… | …01001111110101111100011 |
3 | 10202222110210011011211021101 |
4 | 12203020033021332233203 |
5 | 12233344110032232012 |
6 | 141131332441535231 |
7 | 6031616652500440 |
oct | 643101711765743 |
9 | 122873704154241 |
10 | 28802304961507 |
11 | 91a4a97304730 |
12 | 32920b57a4517 |
13 | 130c079545abc |
14 | 7180790229c7 |
15 | 34e33263ed57 |
hex | 1a320f27ebe3 |
28802304961507 has 32 divisors (see below), whose sum is σ = 37016138833920. Its totient is φ = 21760547851680.
The previous prime is 28802304961471. The next prime is 28802304961567. The reversal of 28802304961507 is 70516940320882.
It is not a de Polignac number, because 28802304961507 - 211 = 28802304959459 is a prime.
It is a super-2 number, since 2×288023049615072 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (28802304961567) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 36802657 + ... + 37577122.
It is an arithmetic number, because the mean of its divisors is an integer number (1156754338560).
It is a 1-persistent number, because it is pandigital, but 2⋅28802304961507 = 57604609923014 is not.
Almost surely, 228802304961507 is an apocalyptic number.
28802304961507 is a deficient number, since it is larger than the sum of its proper divisors (8213833872413).
28802304961507 is a wasteful number, since it uses less digits than its factorization.
28802304961507 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 74379951.
The product of its (nonzero) digits is 5806080, while the sum is 55.
The spelling of 28802304961507 in words is "twenty-eight trillion, eight hundred two billion, three hundred four million, nine hundred sixty-one thousand, five hundred seven".
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