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292314017298113 is a prime number
BaseRepresentation
bin100001001110110111010100…
…1001010011111011011000001
31102022222221120110111201212022
41002131232221022133123001
5301303233101412014423
62513411112232411225
7115366663564445426
oct10235565112373301
91368887513451768
10292314017298113
118515a751177088
12289504b8b46b15
13c71512a6c6ac5
145228106bd5d4d
1523bdb599a5dc8
hex109dba929f6c1

292314017298113 has 2 divisors, whose sum is σ = 292314017298114. Its totient is φ = 292314017298112.

The previous prime is 292314017298103. The next prime is 292314017298211. The reversal of 292314017298113 is 311892710413292.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 150902748925504 + 141411268372609 = 12284248^2 + 11891647^2 .

It is a cyclic number.

It is not a de Polignac number, because 292314017298113 - 210 = 292314017297089 is a prime.

It is not a weakly prime, because it can be changed into another prime (292314017298103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 146157008649056 + 146157008649057.

It is an arithmetic number, because the mean of its divisors is an integer number (146157008649057).

Almost surely, 2292314017298113 is an apocalyptic number.

It is an amenable number.

292314017298113 is a deficient number, since it is larger than the sum of its proper divisors (1).

292314017298113 is an equidigital number, since it uses as much as digits as its factorization.

292314017298113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1306368, while the sum is 53.

The spelling of 292314017298113 in words is "two hundred ninety-two trillion, three hundred fourteen billion, seventeen million, two hundred ninety-eight thousand, one hundred thirteen".