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29233152000113 is a prime number
BaseRepresentation
bin1101010010110010111111…
…01001000000000001110001
310211111122212121220010011112
412221121133221000001301
512312423443403000423
6142101305153123105
76105011521055555
oct651313751000161
9124448777803145
1029233152000113
11935078a219766
1233416b7559495
13134089c88b5b9
14730c6bd21865
1535a64c1cba78
hex1a965fa40071

29233152000113 has 2 divisors, whose sum is σ = 29233152000114. Its totient is φ = 29233152000112.

The previous prime is 29233151999983. The next prime is 29233152000179. The reversal of 29233152000113 is 31100025133292.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22868748208384 + 6364403791729 = 4782128^2 + 2522777^2 .

It is a cyclic number.

It is not a de Polignac number, because 29233152000113 - 230 = 29232078258289 is a prime.

It is a super-3 number, since 3×292331520001133 (a number of 41 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 29233152000113.

It is not a weakly prime, because it can be changed into another prime (29233152300113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14616576000056 + 14616576000057.

It is an arithmetic number, because the mean of its divisors is an integer number (14616576000057).

Almost surely, 229233152000113 is an apocalyptic number.

It is an amenable number.

29233152000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

29233152000113 is an equidigital number, since it uses as much as digits as its factorization.

29233152000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9720, while the sum is 32.

The spelling of 29233152000113 in words is "twenty-nine trillion, two hundred thirty-three billion, one hundred fifty-two million, one hundred thirteen", and thus it is an aban number.