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2940198736583 is a prime number
BaseRepresentation
bin101010110010010001100…
…000000101001011000111
3101102002011111122100001002
4222302101200011023013
5341133011334032313
610130413022523515
7422264602622243
oct52622140051307
911362144570032
102940198736583
11a33a27599429
123b59b673659b
1318434b306c34
14a24409b7423
155173469b058
hex2ac918052c7

2940198736583 has 2 divisors, whose sum is σ = 2940198736584. Its totient is φ = 2940198736582.

The previous prime is 2940198736561. The next prime is 2940198736589. The reversal of 2940198736583 is 3856378910492.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2940198736583 is a prime.

It is a super-2 number, since 2×29401987365832 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2940198736589) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1470099368291 + 1470099368292.

It is an arithmetic number, because the mean of its divisors is an integer number (1470099368292).

It is a 1-persistent number, because it is pandigital, but 2⋅2940198736583 = 5880397473166 is not.

Almost surely, 22940198736583 is an apocalyptic number.

2940198736583 is a deficient number, since it is larger than the sum of its proper divisors (1).

2940198736583 is an equidigital number, since it uses as much as digits as its factorization.

2940198736583 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 78382080, while the sum is 65.

The spelling of 2940198736583 in words is "two trillion, nine hundred forty billion, one hundred ninety-eight million, seven hundred thirty-six thousand, five hundred eighty-three".