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2943129953 is a prime number
BaseRepresentation
bin1010111101101100…
…1001100101100001
321121010000111022002
42233123021211201
522011420124303
61204013253345
7132635122541
oct25733114541
97533014262
102943129953
111280358105
126a1794255
1337b99211a
141dcc41321
151235ad788
hexaf6c9961

2943129953 has 2 divisors, whose sum is σ = 2943129954. Its totient is φ = 2943129952.

The previous prime is 2943129941. The next prime is 2943129967. The reversal of 2943129953 is 3599213492.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2843768929 + 99361024 = 53327^2 + 9968^2 .

It is a cyclic number.

It is not a de Polignac number, because 2943129953 - 228 = 2674694497 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2943129898 and 2943129907.

It is not a weakly prime, because it can be changed into another prime (2943129353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1471564976 + 1471564977.

It is an arithmetic number, because the mean of its divisors is an integer number (1471564977).

Almost surely, 22943129953 is an apocalyptic number.

It is an amenable number.

2943129953 is a deficient number, since it is larger than the sum of its proper divisors (1).

2943129953 is an equidigital number, since it uses as much as digits as its factorization.

2943129953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 524880, while the sum is 47.

The square root of 2943129953 is about 54250.6216830738. The cubic root of 2943129953 is about 1433.0779469933.

The spelling of 2943129953 in words is "two billion, nine hundred forty-three million, one hundred twenty-nine thousand, nine hundred fifty-three".