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2949828499691 is a prime number
BaseRepresentation
bin101010111011001111011…
…110101101100011101011
3101110000000121201222121222
4222323033132231203223
5341312222043442231
610135044342052255
7423055333353323
oct52731736554353
911400017658558
102949828499691
11a38019316a37
123b784371a08b
131852243a4008
14a2ab58c2283
1551ae9cc427b
hex2aecf7ad8eb

2949828499691 has 2 divisors, whose sum is σ = 2949828499692. Its totient is φ = 2949828499690.

The previous prime is 2949828499637. The next prime is 2949828499693. The reversal of 2949828499691 is 1969948289492.

2949828499691 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2949828499691 is a prime.

Together with 2949828499693, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2949828499693) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1474914249845 + 1474914249846.

It is an arithmetic number, because the mean of its divisors is an integer number (1474914249846).

Almost surely, 22949828499691 is an apocalyptic number.

2949828499691 is a deficient number, since it is larger than the sum of its proper divisors (1).

2949828499691 is an equidigital number, since it uses as much as digits as its factorization.

2949828499691 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1451188224, while the sum is 80.

The spelling of 2949828499691 in words is "two trillion, nine hundred forty-nine billion, eight hundred twenty-eight million, four hundred ninety-nine thousand, six hundred ninety-one".