Base | Representation |
---|---|
bin | 101011000101111110100… |
… | …100000001101001010111 |
3 | 101111002202222110112220011 |
4 | 223011332210001221113 |
5 | 342004324043340322 |
6 | 10144232245021051 |
7 | 423644105213611 |
oct | 53057644015127 |
9 | 11432688415804 |
10 | 2961355840087 |
11 | a419a4195437 |
12 | 3b9b200b4787 |
13 | 186340636ca8 |
14 | a348a823db1 |
15 | 52071ccc677 |
hex | 2b17e901a57 |
2961355840087 has 2 divisors, whose sum is σ = 2961355840088. Its totient is φ = 2961355840086.
The previous prime is 2961355840073. The next prime is 2961355840097. The reversal of 2961355840087 is 7800485531692.
2961355840087 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2961355840087 - 231 = 2959208356439 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2961355840097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1480677920043 + 1480677920044.
It is an arithmetic number, because the mean of its divisors is an integer number (1480677920044).
It is a 1-persistent number, because it is pandigital, but 2⋅2961355840087 = 5922711680174 is not.
Almost surely, 22961355840087 is an apocalyptic number.
2961355840087 is a deficient number, since it is larger than the sum of its proper divisors (1).
2961355840087 is an equidigital number, since it uses as much as digits as its factorization.
2961355840087 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14515200, while the sum is 58.
The spelling of 2961355840087 in words is "two trillion, nine hundred sixty-one billion, three hundred fifty-five million, eight hundred forty thousand, eighty-seven".
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