Base | Representation |
---|---|
bin | 1101011110101001010001… |
… | …11001100010000011001101 |
3 | 10212221120200100220122200111 |
4 | 12233110220321202003031 |
5 | 12341111220400330023 |
6 | 143012313445400021 |
7 | 6146303106413533 |
oct | 657245071420315 |
9 | 125846610818614 |
10 | 29640255480013 |
11 | 94983a8553702 |
12 | 33a8591709011 |
13 | 13700aaa94289 |
14 | 74684b69a153 |
15 | 36602753000d |
hex | 1af528e620cd |
29640255480013 has 2 divisors, whose sum is σ = 29640255480014. Its totient is φ = 29640255480012.
The previous prime is 29640255479993. The next prime is 29640255480029. The reversal of 29640255480013 is 31008455204692.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 28857502998724 + 782752481289 = 5371918^2 + 884733^2 .
It is a cyclic number.
It is not a de Polignac number, because 29640255480013 - 225 = 29640221925581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (29640255486013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14820127740006 + 14820127740007.
It is an arithmetic number, because the mean of its divisors is an integer number (14820127740007).
Almost surely, 229640255480013 is an apocalyptic number.
It is an amenable number.
29640255480013 is a deficient number, since it is larger than the sum of its proper divisors (1).
29640255480013 is an equidigital number, since it uses as much as digits as its factorization.
29640255480013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2073600, while the sum is 49.
The spelling of 29640255480013 in words is "twenty-nine trillion, six hundred forty billion, two hundred fifty-five million, four hundred eighty thousand, thirteen".
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