Base | Representation |
---|---|
bin | 101011101001111101111… |
… | …100010000100100101101 |
3 | 101121210112011111102121112 |
4 | 223221331330100210231 |
5 | 343123000012334013 |
6 | 10214103034041405 |
7 | 426512541200201 |
oct | 53517574204455 |
9 | 11553464442545 |
10 | 3000000121133 |
11 | a57324949794 |
12 | 405505b79265 |
13 | 189b8b873092 |
14 | a52b4d28b01 |
15 | 53084769ba8 |
hex | 2ba7df1092d |
3000000121133 has 2 divisors, whose sum is σ = 3000000121134. Its totient is φ = 3000000121132.
The previous prime is 3000000121087. The next prime is 3000000121141. The reversal of 3000000121133 is 3311210000003.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2927120639689 + 72879481444 = 1710883^2 + 269962^2 .
It is a cyclic number.
It is not a de Polignac number, because 3000000121133 - 210 = 3000000120109 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3000000121193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1500000060566 + 1500000060567.
It is an arithmetic number, because the mean of its divisors is an integer number (1500000060567).
Almost surely, 23000000121133 is an apocalyptic number.
It is an amenable number.
3000000121133 is a deficient number, since it is larger than the sum of its proper divisors (1).
3000000121133 is an equidigital number, since it uses as much as digits as its factorization.
3000000121133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 3000000121133 its reverse (3311210000003), we get a palindrome (6311210121136).
The spelling of 3000000121133 in words is "three trillion, one hundred twenty-one thousand, one hundred thirty-three".
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