Base | Representation |
---|---|
bin | 11011111100001001… |
… | …111001000100010011 |
3 | 2212102202202212111212 |
4 | 123330021321010103 |
5 | 442420031132001 |
6 | 21440521330335 |
7 | 2111301651011 |
oct | 337411710423 |
9 | 85382685455 |
10 | 30000255251 |
11 | 117a53a888a |
12 | 59930369ab |
13 | 2aa1454335 |
14 | 16484b38b1 |
15 | ba8b797bb |
hex | 6fc279113 |
30000255251 has 2 divisors, whose sum is σ = 30000255252. Its totient is φ = 30000255250.
The previous prime is 30000255223. The next prime is 30000255253. The reversal of 30000255251 is 15255200003.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 30000255251 - 234 = 12820386067 is a prime.
Together with 30000255253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (30000255253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15000127625 + 15000127626.
It is an arithmetic number, because the mean of its divisors is an integer number (15000127626).
Almost surely, 230000255251 is an apocalyptic number.
30000255251 is a deficient number, since it is larger than the sum of its proper divisors (1).
30000255251 is an equidigital number, since it uses as much as digits as its factorization.
30000255251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1500, while the sum is 23.
Adding to 30000255251 its reverse (15255200003), we get a palindrome (45255455254).
The spelling of 30000255251 in words is "thirty billion, two hundred fifty-five thousand, two hundred fifty-one".
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