Base | Representation |
---|---|
bin | 100010000110111000011100… |
… | …0111001101111001111110111 |
3 | 1110100020222000111222020112222 |
4 | 1010031300320321233033313 |
5 | 303310403121104020043 |
6 | 2542024024010232555 |
7 | 120123140033511512 |
oct | 10415607071571767 |
9 | 1410228014866488 |
10 | 300013010220023 |
11 | 87658891a45381 |
12 | 2979464612575b |
13 | cb5314a944569 |
14 | 54129c86a1d79 |
15 | 24a4060b2dd68 |
hex | 110dc38e6f3f7 |
300013010220023 has 2 divisors, whose sum is σ = 300013010220024. Its totient is φ = 300013010220022.
The previous prime is 300013010219987. The next prime is 300013010220037. The reversal of 300013010220023 is 320022010310003.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 300013010220023 - 212 = 300013010215927 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 300013010219983 and 300013010220010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (300013010220323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 150006505110011 + 150006505110012.
It is an arithmetic number, because the mean of its divisors is an integer number (150006505110012).
Almost surely, 2300013010220023 is an apocalyptic number.
300013010220023 is a deficient number, since it is larger than the sum of its proper divisors (1).
300013010220023 is an equidigital number, since it uses as much as digits as its factorization.
300013010220023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 17.
Adding to 300013010220023 its reverse (320022010310003), we get a palindrome (620035020530026).
The spelling of 300013010220023 in words is "three hundred trillion, thirteen billion, ten million, two hundred twenty thousand, twenty-three".
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