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3001100094131 is a prime number
BaseRepresentation
bin101011101010111111100…
…000010100101010110011
3101121220100211021211220012
4223222333200110222303
5343132223111003011
610214404130205135
7426552025621436
oct53527740245263
911556324254805
103001100094131
11a57839845787
124057724237ab
1318a005714689
14a537b05b81d
15530eb0e7a8b
hex2babf814ab3

3001100094131 has 2 divisors, whose sum is σ = 3001100094132. Its totient is φ = 3001100094130.

The previous prime is 3001100094107. The next prime is 3001100094133. The reversal of 3001100094131 is 1314900011003.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3001100094131 is a prime.

It is a super-2 number, since 2×30011000941312 (a number of 26 digits) contains 22 as substring.

Together with 3001100094133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 3001100094097 and 3001100094106.

It is not a weakly prime, because it can be changed into another prime (3001100094133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1500550047065 + 1500550047066.

It is an arithmetic number, because the mean of its divisors is an integer number (1500550047066).

Almost surely, 23001100094131 is an apocalyptic number.

3001100094131 is a deficient number, since it is larger than the sum of its proper divisors (1).

3001100094131 is an equidigital number, since it uses as much as digits as its factorization.

3001100094131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 23.

The spelling of 3001100094131 in words is "three trillion, one billion, one hundred million, ninety-four thousand, one hundred thirty-one".