Base | Representation |
---|---|
bin | 101011110100001101100… |
… | …101011101111001101111 |
3 | 101122211220202201011211122 |
4 | 223310031211131321233 |
5 | 343313012000000421 |
6 | 10223122335411155 |
7 | 430352246500205 |
oct | 53641545357157 |
9 | 11584822634748 |
10 | 3011000000111 |
11 | a60a5a004664 |
12 | 407675983abb |
13 | 18ac227575cc |
14 | a5a39ba7075 |
15 | 534ca2d32ab |
hex | 2bd0d95de6f |
3011000000111 has 2 divisors, whose sum is σ = 3011000000112. Its totient is φ = 3011000000110.
The previous prime is 3011000000069. The next prime is 3011000000137. The reversal of 3011000000111 is 1110000001103.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3011000000111 - 210 = 3010999999087 is a prime.
It is a super-3 number, since 3×30110000001113 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3011000003111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1505500000055 + 1505500000056.
It is an arithmetic number, because the mean of its divisors is an integer number (1505500000056).
Almost surely, 23011000000111 is an apocalyptic number.
3011000000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
3011000000111 is an equidigital number, since it uses as much as digits as its factorization.
3011000000111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 8.
Adding to 3011000000111 its reverse (1110000001103), we get a palindrome (4121000001214).
The spelling of 3011000000111 in words is "three trillion, eleven billion, one hundred eleven", and thus it is an aban number.
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