Base | Representation |
---|---|
bin | 1101101100010110101110… |
… | …01000001101110010010111 |
3 | 10221121121121100201201220022 |
4 | 12312023113020031302113 |
5 | 12421321000440000043 |
6 | 144012542023255355 |
7 | 6225320553645566 |
oct | 666132710156227 |
9 | 127547540651808 |
10 | 30111330000023 |
11 | 965a163869938 |
12 | 346393b5aa55b |
13 | 13a56423490cc |
14 | 76157905dbdd |
15 | 3733e8a3a868 |
hex | 1b62d720dc97 |
30111330000023 has 2 divisors, whose sum is σ = 30111330000024. Its totient is φ = 30111330000022.
The previous prime is 30111330000001. The next prime is 30111330000029. The reversal of 30111330000023 is 32000003311103.
It is a strong prime.
It is an emirp because it is prime and its reverse (32000003311103) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 30111330000023 - 212 = 30111329995927 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 30111329999956 and 30111330000010.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (30111330000029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15055665000011 + 15055665000012.
It is an arithmetic number, because the mean of its divisors is an integer number (15055665000012).
Almost surely, 230111330000023 is an apocalyptic number.
30111330000023 is a deficient number, since it is larger than the sum of its proper divisors (1).
30111330000023 is an equidigital number, since it uses as much as digits as its factorization.
30111330000023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 30111330000023 its reverse (32000003311103), we get a palindrome (62111333311126).
The spelling of 30111330000023 in words is "thirty trillion, one hundred eleven billion, three hundred thirty million, twenty-three", and thus it is an aban number.
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