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30112333220131 is a prime number
BaseRepresentation
bin1101101100011000100101…
…11011001100100100100011
310221121201012021110121011121
412312030102323030210203
512421330024301021011
6144013225341553111
76225354455120551
oct666142273144443
9127551167417147
1030112333220131
11965a629091a68
123463b7b575797
1313a5772142b86
147616323a8bd1
15373456b55e71
hex1b6312ecc923

30112333220131 has 2 divisors, whose sum is σ = 30112333220132. Its totient is φ = 30112333220130.

The previous prime is 30112333220077. The next prime is 30112333220183. The reversal of 30112333220131 is 13102233321103.

It is a strong prime.

It is an emirp because it is prime and its reverse (13102233321103) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 30112333220131 - 27 = 30112333220003 is a prime.

It is a super-2 number, since 2×301123332201312 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 30112333220096 and 30112333220105.

It is not a weakly prime, because it can be changed into another prime (30112333320131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15056166610065 + 15056166610066.

It is an arithmetic number, because the mean of its divisors is an integer number (15056166610066).

Almost surely, 230112333220131 is an apocalyptic number.

30112333220131 is a deficient number, since it is larger than the sum of its proper divisors (1).

30112333220131 is an equidigital number, since it uses as much as digits as its factorization.

30112333220131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 30112333220131 its reverse (13102233321103), we get a palindrome (43214566541234).

The spelling of 30112333220131 in words is "thirty trillion, one hundred twelve billion, three hundred thirty-three million, two hundred twenty thousand, one hundred thirty-one".