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3011324331413 is a prime number
BaseRepresentation
bin101011110100100000111…
…010101100010110010101
3101122212202100222220202002
4223310200322230112111
5343314143012101123
610223214443125045
7430363265325416
oct53644072542625
911585670886662
103011324331413
11a61106097562
12407746513785
1318ac749c4118
14a5a6acb180d
15534e89eb528
hex2bd20eac595

3011324331413 has 2 divisors, whose sum is σ = 3011324331414. Its totient is φ = 3011324331412.

The previous prime is 3011324331359. The next prime is 3011324331419. The reversal of 3011324331413 is 3141334231103.

3011324331413 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2738833023364 + 272491308049 = 1654942^2 + 522007^2 .

It is a cyclic number.

It is not a de Polignac number, because 3011324331413 - 212 = 3011324327317 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3011324331419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1505662165706 + 1505662165707.

It is an arithmetic number, because the mean of its divisors is an integer number (1505662165707).

Almost surely, 23011324331413 is an apocalyptic number.

It is an amenable number.

3011324331413 is a deficient number, since it is larger than the sum of its proper divisors (1).

3011324331413 is an equidigital number, since it uses as much as digits as its factorization.

3011324331413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 3011324331413 its reverse (3141334231103), we get a palindrome (6152658562516).

The spelling of 3011324331413 in words is "three trillion, eleven billion, three hundred twenty-four million, three hundred thirty-one thousand, four hundred thirteen".