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3011331120000 = 2735472377933
BaseRepresentation
bin101011110100100001010…
…100100101101110000000
3101122212202211202210221020
4223310201110211232000
5343314201231320000
610223215244425440
7430363410121260
oct53644124455600
911585684683836
103011331120000
11a61109a03965
12407748848280
1318ac76230038
14a5a6bb5b7a0
15534e93dcba0
hex2bd21525b80

3011331120000 has 640 divisors, whose sum is σ = 11920086351360. Its totient is φ = 658369536000.

The previous prime is 3011331119989. The next prime is 3011331120011. The reversal of 3011331120000 is 211331103.

It is an interprime number because it is at equal distance from previous prime (3011331119989) and next prime (3011331120011).

It is a tau number, because it is divible by the number of its divisors (640).

It is a super-2 number, since 2×30113311200002 (a number of 26 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 38601034 + ... + 38678966.

It is an arithmetic number, because the mean of its divisors is an integer number (18625134924).

Almost surely, 23011331120000 is an apocalyptic number.

3011331120000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3011331120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (5960043175680).

3011331120000 is an abundant number, since it is smaller than the sum of its proper divisors (8908755231360).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3011331120000 is an equidigital number, since it uses as much as digits as its factorization.

3011331120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 78000 (or 77973 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 3011331120000 its reverse (211331103), we get a palindrome (3011542451103).

The spelling of 3011331120000 in words is "three trillion, eleven billion, three hundred thirty-one million, one hundred twenty thousand".