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3012113111207 is a prime number
BaseRepresentation
bin101011110101001111111…
…011101001100010100111
3101122221210100020002012112
4223311033323221202213
5343322301424024312
610223425021311235
7430421654001104
oct53651773514247
911587710202175
103012113111207
11a61480364492
1240792670551b
1318b06c248c25
14a5b03959aab
1553542da8d22
hex2bd4fee98a7

3012113111207 has 2 divisors, whose sum is σ = 3012113111208. Its totient is φ = 3012113111206.

The previous prime is 3012113111177. The next prime is 3012113111251. The reversal of 3012113111207 is 7021113112103.

3012113111207 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 3012113111207 - 222 = 3012108916903 is a prime.

It is a super-2 number, since 2×30121131112072 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3012113111107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1506056555603 + 1506056555604.

It is an arithmetic number, because the mean of its divisors is an integer number (1506056555604).

Almost surely, 23012113111207 is an apocalyptic number.

3012113111207 is a deficient number, since it is larger than the sum of its proper divisors (1).

3012113111207 is an equidigital number, since it uses as much as digits as its factorization.

3012113111207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 252, while the sum is 23.

The spelling of 3012113111207 in words is "three trillion, twelve billion, one hundred thirteen million, one hundred eleven thousand, two hundred seven".