Base | Representation |
---|---|
bin | 1101101100101100011101… |
… | …10010000011111100000011 |
3 | 10221122201201202000211001012 |
4 | 12312112032302003330003 |
5 | 12422013401242303401 |
6 | 144022152104231135 |
7 | 6226213022652002 |
oct | 666261662037403 |
9 | 127581652024035 |
10 | 30123001134851 |
11 | 9664102921209 |
12 | 346605816b4ab |
13 | 13a6782317551 |
14 | 761d65112c39 |
15 | 37387d4998bb |
hex | 1b658ec83f03 |
30123001134851 has 2 divisors, whose sum is σ = 30123001134852. Its totient is φ = 30123001134850.
The previous prime is 30123001134829. The next prime is 30123001134857. The reversal of 30123001134851 is 15843110032103.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-30123001134851 is a prime.
It is not a weakly prime, because it can be changed into another prime (30123001134857) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15061500567425 + 15061500567426.
It is an arithmetic number, because the mean of its divisors is an integer number (15061500567426).
Almost surely, 230123001134851 is an apocalyptic number.
30123001134851 is a deficient number, since it is larger than the sum of its proper divisors (1).
30123001134851 is an equidigital number, since it uses as much as digits as its factorization.
30123001134851 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 32.
Adding to 30123001134851 its reverse (15843110032103), we get a palindrome (45966111166954).
The spelling of 30123001134851 in words is "thirty trillion, one hundred twenty-three billion, one million, one hundred thirty-four thousand, eight hundred fifty-one".
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