Base | Representation |
---|---|
bin | 101011110110000101000… |
… | …110110110011100110011 |
3 | 101200001002111220220222221 |
4 | 223312011012312130303 |
5 | 343331113320140430 |
6 | 10224053330541511 |
7 | 430453035655033 |
oct | 53660506663463 |
9 | 11601074826887 |
10 | 3013005240115 |
11 | a61898a00102 |
12 | 407b35437897 |
13 | 18b182017a60 |
14 | a5b8a2278c3 |
15 | 5359637d57a |
hex | 2bd851b6733 |
3013005240115 has 32 divisors (see below), whose sum is σ = 3985731864576. Its totient is φ = 2172453575040.
The previous prime is 3013005240053. The next prime is 3013005240139. The reversal of 3013005240115 is 5110425003103.
It is a happy number.
It is not a de Polignac number, because 3013005240115 - 215 = 3013005207347 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 3013005240115.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7538970 + ... + 7928560.
It is an arithmetic number, because the mean of its divisors is an integer number (124554120768).
Almost surely, 23013005240115 is an apocalyptic number.
3013005240115 is a deficient number, since it is larger than the sum of its proper divisors (972726624461).
3013005240115 is a wasteful number, since it uses less digits than its factorization.
3013005240115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 392419.
The product of its (nonzero) digits is 1800, while the sum is 25.
The spelling of 3013005240115 in words is "three trillion, thirteen billion, five million, two hundred forty thousand, one hundred fifteen".
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