Base | Representation |
---|---|
bin | 11100000011111110… |
… | …001100000011110001 |
3 | 2212202220112222012111 |
4 | 130003332030003301 |
5 | 443202114430131 |
6 | 21501524325321 |
7 | 2114453500633 |
oct | 340376140361 |
9 | 85686488174 |
10 | 30131405041 |
11 | 11862435641 |
12 | 5a0ab43841 |
13 | 2ac268326a |
14 | 165ba92a53 |
15 | bb5433ab1 |
hex | 703f8c0f1 |
30131405041 has 2 divisors, whose sum is σ = 30131405042. Its totient is φ = 30131405040.
The previous prime is 30131405011. The next prime is 30131405071. The reversal of 30131405041 is 14050413103.
It is a balanced prime because it is at equal distance from previous prime (30131405011) and next prime (30131405071).
It can be written as a sum of positive squares in only one way, i.e., 25761534016 + 4369871025 = 160504^2 + 66105^2 .
It is a cyclic number.
It is not a de Polignac number, because 30131405041 - 211 = 30131402993 is a prime.
It is not a weakly prime, because it can be changed into another prime (30131405011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15065702520 + 15065702521.
It is an arithmetic number, because the mean of its divisors is an integer number (15065702521).
Almost surely, 230131405041 is an apocalyptic number.
It is an amenable number.
30131405041 is a deficient number, since it is larger than the sum of its proper divisors (1).
30131405041 is an equidigital number, since it uses as much as digits as its factorization.
30131405041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 30131405041 its reverse (14050413103), we get a palindrome (44181818144).
The spelling of 30131405041 in words is "thirty billion, one hundred thirty-one million, four hundred five thousand, forty-one".
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