Base | Representation |
---|---|
bin | 101011110110101011001… |
… | …001101010010111010101 |
3 | 101200002201222221110101201 |
4 | 223312223021222113111 |
5 | 343333420214330003 |
6 | 10224240531152501 |
7 | 430504616121604 |
oct | 53665311522725 |
9 | 11602658843351 |
10 | 3013643511253 |
11 | a62096218711 |
12 | 408093145731 |
13 | 18b25432329b |
14 | a5c0acd3a3b |
15 | 535d240ab1d |
hex | 2bdab26a5d5 |
3013643511253 has 2 divisors, whose sum is σ = 3013643511254. Its totient is φ = 3013643511252.
The previous prime is 3013643511191. The next prime is 3013643511269. The reversal of 3013643511253 is 3521153463103.
3013643511253 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2916522775089 + 97120736164 = 1707783^2 + 311642^2 .
It is a cyclic number.
It is not a de Polignac number, because 3013643511253 - 29 = 3013643510741 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3013643511293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1506821755626 + 1506821755627.
It is an arithmetic number, because the mean of its divisors is an integer number (1506821755627).
Almost surely, 23013643511253 is an apocalyptic number.
It is an amenable number.
3013643511253 is a deficient number, since it is larger than the sum of its proper divisors (1).
3013643511253 is an equidigital number, since it uses as much as digits as its factorization.
3013643511253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 37.
Adding to 3013643511253 its reverse (3521153463103), we get a palindrome (6534796974356).
The spelling of 3013643511253 in words is "three trillion, thirteen billion, six hundred forty-three million, five hundred eleven thousand, two hundred fifty-three".
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