Base | Representation |
---|---|
bin | 101011110110111010101… |
… | …111000111001001010111 |
3 | 101200010102012221210021221 |
4 | 223312322233013021113 |
5 | 343334434134033321 |
6 | 10224322511351211 |
7 | 430514242456663 |
oct | 53667257071127 |
9 | 11603365853257 |
10 | 3013904986711 |
11 | a6220a87a033 |
12 | 408146822507 |
13 | 18b296552ca8 |
14 | a5c339198a3 |
15 | 535ea359e41 |
hex | 2bdbabc7257 |
3013904986711 has 2 divisors, whose sum is σ = 3013904986712. Its totient is φ = 3013904986710.
The previous prime is 3013904986699. The next prime is 3013904986739. The reversal of 3013904986711 is 1176894093103.
3013904986711 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (1176894093103) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3013904986711 - 25 = 3013904986679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3013904486711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1506952493355 + 1506952493356.
It is an arithmetic number, because the mean of its divisors is an integer number (1506952493356).
Almost surely, 23013904986711 is an apocalyptic number.
3013904986711 is a deficient number, since it is larger than the sum of its proper divisors (1).
3013904986711 is an equidigital number, since it uses as much as digits as its factorization.
3013904986711 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 979776, while the sum is 52.
The spelling of 3013904986711 in words is "three trillion, thirteen billion, nine hundred four million, nine hundred eighty-six thousand, seven hundred eleven".
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