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3014000000311 is a prime number
BaseRepresentation
bin101011110111000000011…
…001100011110100110111
3101200010122211201222110011
4223313000121203310313
5343340133000002221
610224340144041051
7430516505203366
oct53670031436467
911603584658404
103014000000311
11a62259475173
12408172603187
1318b2b013bc61
14a5c423ad7dd
15536038771e1
hex2bdc0663d37

3014000000311 has 2 divisors, whose sum is σ = 3014000000312. Its totient is φ = 3014000000310.

The previous prime is 3014000000299. The next prime is 3014000000321. The reversal of 3014000000311 is 1130000004103.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3014000000311 - 221 = 3013997903159 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3014000000291 and 3014000000300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3014000000321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1507000000155 + 1507000000156.

It is an arithmetic number, because the mean of its divisors is an integer number (1507000000156).

Almost surely, 23014000000311 is an apocalyptic number.

3014000000311 is a deficient number, since it is larger than the sum of its proper divisors (1).

3014000000311 is an equidigital number, since it uses as much as digits as its factorization.

3014000000311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 3014000000311 its reverse (1130000004103), we get a palindrome (4144000004414).

The spelling of 3014000000311 in words is "three trillion, fourteen billion, three hundred eleven", and thus it is an aban number.