Base | Representation |
---|---|
bin | 101011110111011001100… |
… | …000110001011001111101 |
3 | 101200011202012112022020202 |
4 | 223313121200301121331 |
5 | 343342013324240331 |
6 | 10224450034253245 |
7 | 430533112315523 |
oct | 53673140613175 |
9 | 11604665468222 |
10 | 3014421321341 |
11 | a62455282971 |
12 | 40826b727225 |
13 | 18b349507041 |
14 | a5c82324313 |
15 | 5362a84cecb |
hex | 2bdd983167d |
3014421321341 has 2 divisors, whose sum is σ = 3014421321342. Its totient is φ = 3014421321340.
The previous prime is 3014421321239. The next prime is 3014421321371. The reversal of 3014421321341 is 1431231244103.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2009958352900 + 1004462968441 = 1417730^2 + 1002229^2 .
It is an emirp because it is prime and its reverse (1431231244103) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3014421321341 - 234 = 2997241452157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3014421321371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1507210660670 + 1507210660671.
It is an arithmetic number, because the mean of its divisors is an integer number (1507210660671).
Almost surely, 23014421321341 is an apocalyptic number.
It is an amenable number.
3014421321341 is a deficient number, since it is larger than the sum of its proper divisors (1).
3014421321341 is an equidigital number, since it uses as much as digits as its factorization.
3014421321341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 3014421321341 its reverse (1431231244103), we get a palindrome (4445652565444).
The spelling of 3014421321341 in words is "three trillion, fourteen billion, four hundred twenty-one million, three hundred twenty-one thousand, three hundred forty-one".
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