Base | Representation |
---|---|
bin | 101011111111011001100… |
… | …111111000100001111001 |
3 | 101200222220222111220110101 |
4 | 223333121213320201321 |
5 | 344012112324320441 |
6 | 10232430354315401 |
7 | 431256040356541 |
oct | 53773147704171 |
9 | 11628828456411 |
10 | 3023013120121 |
11 | a66064107515 |
12 | 409a68b88b61 |
13 | 18c0b8533b47 |
14 | a645943c321 |
15 | 5397ec96231 |
hex | 2bfd99f8879 |
3023013120121 has 2 divisors, whose sum is σ = 3023013120122. Its totient is φ = 3023013120120.
The previous prime is 3023013120119. The next prime is 3023013120133. The reversal of 3023013120121 is 1210213103203.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1562347503721 + 1460665616400 = 1249939^2 + 1208580^2 .
It is a cyclic number.
It is not a de Polignac number, because 3023013120121 - 21 = 3023013120119 is a prime.
Together with 3023013120119, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3023013120181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1511506560060 + 1511506560061.
It is an arithmetic number, because the mean of its divisors is an integer number (1511506560061).
Almost surely, 23023013120121 is an apocalyptic number.
It is an amenable number.
3023013120121 is a deficient number, since it is larger than the sum of its proper divisors (1).
3023013120121 is an equidigital number, since it uses as much as digits as its factorization.
3023013120121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 3023013120121 its reverse (1210213103203), we get a palindrome (4233226223324).
The spelling of 3023013120121 in words is "three trillion, twenty-three billion, thirteen million, one hundred twenty thousand, one hundred twenty-one".
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