Base | Representation |
---|---|
bin | 1101110000001010001001… |
… | …00000001111010011111111 |
3 | 10222002002220221210110120102 |
4 | 12320011010200033103333 |
5 | 12430441121043030101 |
6 | 144152553415511315 |
7 | 6240625204623614 |
oct | 670050440172377 |
9 | 128062827713512 |
10 | 30242014033151 |
11 | 96aa6255721a8 |
12 | 348513138853b |
13 | 13b4a6ab5c56b |
14 | 767a1530850b |
15 | 3769e696a86b |
hex | 1b814480f4ff |
30242014033151 has 2 divisors, whose sum is σ = 30242014033152. Its totient is φ = 30242014033150.
The previous prime is 30242014033081. The next prime is 30242014033157. The reversal of 30242014033151 is 15133041024203.
It is a strong prime.
It is an emirp because it is prime and its reverse (15133041024203) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 30242014033151 - 210 = 30242014032127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (30242014033157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15121007016575 + 15121007016576.
It is an arithmetic number, because the mean of its divisors is an integer number (15121007016576).
Almost surely, 230242014033151 is an apocalyptic number.
30242014033151 is a deficient number, since it is larger than the sum of its proper divisors (1).
30242014033151 is an equidigital number, since it uses as much as digits as its factorization.
30242014033151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 30242014033151 its reverse (15133041024203), we get a palindrome (45375055057354).
The spelling of 30242014033151 in words is "thirty trillion, two hundred forty-two billion, fourteen million, thirty-three thousand, one hundred fifty-one".
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