Base | Representation |
---|---|
bin | 100010100100010001110010… |
… | …0000101000010100111100001 |
3 | 1110212120012022220021101020002 |
4 | 1011020203210011002213201 |
5 | 304323101323221020441 |
6 | 2554400031152025345 |
7 | 121021054351453103 |
oct | 10510434405024741 |
9 | 1425505286241202 |
10 | 304053151345121 |
11 | 889762433153a2 |
12 | 2a127655232255 |
13 | 10087120b04a09 |
14 | 5512372c27573 |
15 | 25241c0b9ab9b |
hex | 11488e41429e1 |
304053151345121 has 2 divisors, whose sum is σ = 304053151345122. Its totient is φ = 304053151345120.
The previous prime is 304053151345081. The next prime is 304053151345157. The reversal of 304053151345121 is 121543151350403.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 259476684558400 + 44576466786721 = 16108280^2 + 6676561^2 .
It is a cyclic number.
It is not a de Polignac number, because 304053151345121 - 234 = 304035971475937 is a prime.
It is not a weakly prime, because it can be changed into another prime (304053151395121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 152026575672560 + 152026575672561.
It is an arithmetic number, because the mean of its divisors is an integer number (152026575672561).
Almost surely, 2304053151345121 is an apocalyptic number.
It is an amenable number.
304053151345121 is a deficient number, since it is larger than the sum of its proper divisors (1).
304053151345121 is an equidigital number, since it uses as much as digits as its factorization.
304053151345121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108000, while the sum is 38.
The spelling of 304053151345121 in words is "three hundred four trillion, fifty-three billion, one hundred fifty-one million, three hundred forty-five thousand, one hundred twenty-one".
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