Base | Representation |
---|---|
bin | 101100010000001011100… |
… | …001101001001010001011 |
3 | 101202201102121212010021011 |
4 | 230100023201221022023 |
5 | 344311012213324113 |
6 | 10245010251224351 |
7 | 432464364216055 |
oct | 54201341511213 |
9 | 11681377763234 |
10 | 3041030214283 |
11 | a7276a304a86 |
12 | 411456a480b7 |
13 | 1909ca16acc9 |
14 | a72882388d5 |
15 | 541868c963d |
hex | 2c40b86928b |
3041030214283 has 2 divisors, whose sum is σ = 3041030214284. Its totient is φ = 3041030214282.
The previous prime is 3041030214253. The next prime is 3041030214289. The reversal of 3041030214283 is 3824120301403.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3041030214283 - 25 = 3041030214251 is a prime.
It is not a weakly prime, because it can be changed into another prime (3041030214289) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1520515107141 + 1520515107142.
It is an arithmetic number, because the mean of its divisors is an integer number (1520515107142).
Almost surely, 23041030214283 is an apocalyptic number.
3041030214283 is a deficient number, since it is larger than the sum of its proper divisors (1).
3041030214283 is an equidigital number, since it uses as much as digits as its factorization.
3041030214283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 3041030214283 its reverse (3824120301403), we get a palindrome (6865150515686).
The spelling of 3041030214283 in words is "three trillion, forty-one billion, thirty million, two hundred fourteen thousand, two hundred eighty-three".
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