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3041341340441 is a prime number
BaseRepresentation
bin101100010000011110000…
…100011111101100011001
3101202202020022021222010012
4230100132010133230121
5344312131340343231
610245101203531305
7432505162565315
oct54203604375431
911682208258105
103041341340441
11a72909998738
12411523089b35
13190a49763121
14a72b76a6b45
15541a3d84e2b
hex2c41e11fb19

3041341340441 has 2 divisors, whose sum is σ = 3041341340442. Its totient is φ = 3041341340440.

The previous prime is 3041341340423. The next prime is 3041341340449. The reversal of 3041341340441 is 1440431431403.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2949170809225 + 92170531216 = 1717315^2 + 303596^2 .

It is a cyclic number.

It is not a de Polignac number, because 3041341340441 - 26 = 3041341340377 is a prime.

It is a super-3 number, since 3×30413413404413 (a number of 38 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3041341340398 and 3041341340407.

It is not a weakly prime, because it can be changed into another prime (3041341340449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1520670670220 + 1520670670221.

It is an arithmetic number, because the mean of its divisors is an integer number (1520670670221).

Almost surely, 23041341340441 is an apocalyptic number.

It is an amenable number.

3041341340441 is a deficient number, since it is larger than the sum of its proper divisors (1).

3041341340441 is an equidigital number, since it uses as much as digits as its factorization.

3041341340441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 3041341340441 its reverse (1440431431403), we get a palindrome (4481772771844).

The spelling of 3041341340441 in words is "three trillion, forty-one billion, three hundred forty-one million, three hundred forty thousand, four hundred forty-one".