Base | Representation |
---|---|
bin | 101100010001000110000… |
… | …111001001000110111011 |
3 | 101202210222010101001112211 |
4 | 230101012013021012323 |
5 | 344320020324414003 |
6 | 10245252002315551 |
7 | 432530630624131 |
oct | 54210607110673 |
9 | 11683863331484 |
10 | 3042013123003 |
11 | a73124114938 |
12 | 411690058bb7 |
13 | 190b259a29ba |
14 | a733c9b7751 |
15 | 541e2d3196d |
hex | 2c4461c91bb |
3042013123003 has 2 divisors, whose sum is σ = 3042013123004. Its totient is φ = 3042013123002.
The previous prime is 3042013123001. The next prime is 3042013123067. The reversal of 3042013123003 is 3003213102403.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 3042013123003 - 21 = 3042013123001 is a prime.
Together with 3042013123001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3042013123001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1521006561501 + 1521006561502.
It is an arithmetic number, because the mean of its divisors is an integer number (1521006561502).
Almost surely, 23042013123003 is an apocalyptic number.
3042013123003 is a deficient number, since it is larger than the sum of its proper divisors (1).
3042013123003 is an equidigital number, since it uses as much as digits as its factorization.
3042013123003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 22.
Adding to 3042013123003 its reverse (3003213102403), we get a palindrome (6045226225406).
The spelling of 3042013123003 in words is "three trillion, forty-two billion, thirteen million, one hundred twenty-three thousand, three".
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