Base | Representation |
---|---|
bin | 1101110111100100110011… |
… | …11010111101100011011111 |
3 | 10222222110200220221122012001 |
4 | 12323302121322331203133 |
5 | 12444130022121002002 |
6 | 144510020510423131 |
7 | 6265216243231123 |
oct | 673623172754337 |
9 | 128873626848161 |
10 | 30496850172127 |
11 | 9798706964219 |
12 | 35065b1501aa7 |
13 | 1402ac0b37041 |
14 | 7760ac125583 |
15 | 37d45e11ea87 |
hex | 1bbc99ebd8df |
30496850172127 has 2 divisors, whose sum is σ = 30496850172128. Its totient is φ = 30496850172126.
The previous prime is 30496850172091. The next prime is 30496850172143. The reversal of 30496850172127 is 72127105869403.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 30496850172127 - 27 = 30496850171999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (30496850172727) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15248425086063 + 15248425086064.
It is an arithmetic number, because the mean of its divisors is an integer number (15248425086064).
It is a 1-persistent number, because it is pandigital, but 2⋅30496850172127 = 60993700344254 is not.
Almost surely, 230496850172127 is an apocalyptic number.
30496850172127 is a deficient number, since it is larger than the sum of its proper divisors (1).
30496850172127 is an equidigital number, since it uses as much as digits as its factorization.
30496850172127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5080320, while the sum is 55.
The spelling of 30496850172127 in words is "thirty trillion, four hundred ninety-six billion, eight hundred fifty million, one hundred seventy-two thousand, one hundred twenty-seven".
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