Base | Representation |
---|---|
bin | 101100011001100100101… |
… | …010100101101011010101 |
3 | 101210200110111102011021212 |
4 | 230121210222211223111 |
5 | 344442141102304013 |
6 | 10253355125351205 |
7 | 433302330151553 |
oct | 54314452455325 |
9 | 11720414364255 |
10 | 3051115666133 |
11 | a76a75284257 |
12 | 4133b0568505 |
13 | 1919467771b2 |
14 | a7963882bd3 |
15 | 545770166a8 |
hex | 2c664aa5ad5 |
3051115666133 has 2 divisors, whose sum is σ = 3051115666134. Its totient is φ = 3051115666132.
The previous prime is 3051115666103. The next prime is 3051115666187. The reversal of 3051115666133 is 3316665111503.
3051115666133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2066113010404 + 985002655729 = 1437398^2 + 992473^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3051115666133 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3051115666103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1525557833066 + 1525557833067.
It is an arithmetic number, because the mean of its divisors is an integer number (1525557833067).
Almost surely, 23051115666133 is an apocalyptic number.
It is an amenable number.
3051115666133 is a deficient number, since it is larger than the sum of its proper divisors (1).
3051115666133 is an equidigital number, since it uses as much as digits as its factorization.
3051115666133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145800, while the sum is 41.
The spelling of 3051115666133 in words is "three trillion, fifty-one billion, one hundred fifteen million, six hundred sixty-six thousand, one hundred thirty-three".
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