Base | Representation |
---|---|
bin | 101100011010110001111… |
… | …111111101010001100011 |
3 | 101210210210220210022101221 |
4 | 230122301333331101203 |
5 | 400002320224112233 |
6 | 10254131554235511 |
7 | 433346433241021 |
oct | 54326177752143 |
9 | 11723726708357 |
10 | 3052413113443 |
11 | a77580698661 |
12 | 4136b2b85b97 |
13 | 191ac24ca2b5 |
14 | a7a47cdb711 |
15 | 54600da042d |
hex | 2c6b1ffd463 |
3052413113443 has 2 divisors, whose sum is σ = 3052413113444. Its totient is φ = 3052413113442.
The previous prime is 3052413113423. The next prime is 3052413113461. The reversal of 3052413113443 is 3443113142503.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3052413113443 - 225 = 3052379559011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 3052413113399 and 3052413113408.
It is not a weakly prime, because it can be changed into another prime (3052413113423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526206556721 + 1526206556722.
It is an arithmetic number, because the mean of its divisors is an integer number (1526206556722).
Almost surely, 23052413113443 is an apocalyptic number.
3052413113443 is a deficient number, since it is larger than the sum of its proper divisors (1).
3052413113443 is an equidigital number, since it uses as much as digits as its factorization.
3052413113443 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 3052413113443 its reverse (3443113142503), we get a palindrome (6495526255946).
The spelling of 3052413113443 in words is "three trillion, fifty-two billion, four hundred thirteen million, one hundred thirteen thousand, four hundred forty-three".
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