Base | Representation |
---|---|
bin | 11100011011011000… |
… | …101000001100011101 |
3 | 2220210021200122001021 |
4 | 130123120220030131 |
5 | 1000003144240442 |
6 | 22004515444141 |
7 | 2130263343466 |
oct | 343330501435 |
9 | 86707618037 |
10 | 30524211997 |
11 | 11a44138294 |
12 | 5aba5b6651 |
13 | 2b55b76806 |
14 | 1697d03d6d |
15 | bd9b75e67 |
hex | 71b62831d |
30524211997 has 2 divisors, whose sum is σ = 30524211998. Its totient is φ = 30524211996.
The previous prime is 30524211989. The next prime is 30524212001. The reversal of 30524211997 is 79911242503.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16745912836 + 13778299161 = 129406^2 + 117381^2 .
It is an emirp because it is prime and its reverse (79911242503) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 30524211997 - 23 = 30524211989 is a prime.
It is a super-4 number, since 4×305242119974 (a number of 43 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (30524211917) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15262105998 + 15262105999.
It is an arithmetic number, because the mean of its divisors is an integer number (15262105999).
Almost surely, 230524211997 is an apocalyptic number.
It is an amenable number.
30524211997 is a deficient number, since it is larger than the sum of its proper divisors (1).
30524211997 is an equidigital number, since it uses as much as digits as its factorization.
30524211997 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 136080, while the sum is 43.
The spelling of 30524211997 in words is "thirty billion, five hundred twenty-four million, two hundred eleven thousand, nine hundred ninety-seven".
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