Base | Representation |
---|---|
bin | 101100011011010110100… |
… | …000000010111111100001 |
3 | 101210212101121010001000221 |
4 | 230123112200002333201 |
5 | 400010044012131444 |
6 | 10254312432043041 |
7 | 433400550420616 |
oct | 54332640027741 |
9 | 11725347101027 |
10 | 3053025505249 |
11 | a7786533a695 |
12 | 413844093481 |
13 | 191b8c344305 |
14 | a7aa538c50d |
15 | 54639a19a84 |
hex | 2c6d6802fe1 |
3053025505249 has 2 divisors, whose sum is σ = 3053025505250. Its totient is φ = 3053025505248.
The previous prime is 3053025505247. The next prime is 3053025505393. The reversal of 3053025505249 is 9425055203503.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1721383360225 + 1331642145024 = 1312015^2 + 1153968^2 .
It is a cyclic number.
It is not a de Polignac number, because 3053025505249 - 21 = 3053025505247 is a prime.
Together with 3053025505247, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (3053025505241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1526512752624 + 1526512752625.
It is an arithmetic number, because the mean of its divisors is an integer number (1526512752625).
Almost surely, 23053025505249 is an apocalyptic number.
It is an amenable number.
3053025505249 is a deficient number, since it is larger than the sum of its proper divisors (1).
3053025505249 is an equidigital number, since it uses as much as digits as its factorization.
3053025505249 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810000, while the sum is 43.
The spelling of 3053025505249 in words is "three trillion, fifty-three billion, twenty-five million, five hundred five thousand, two hundred forty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •